Created By : Naaz Fatima

Reviewed By : Phani Ponnapalli

Last Updated : Apr 10, 2023

You can find the hydraulic pressure of a device easily by giving the required input details on Hydraulic Pressure Calculator. Enter the area, the force of the first piston and the area of the second piston of the hydraulic system and press the calculate button to obtain the liquid pressure and force of the second piston.

Choose a Calculation
Area(1st piston):
Force(1st piston):

### Step by Step Process to Evaluate Acceleration

The hydraulic pressure acting on a system is calculated using Pascal's law. Obtain the simple steps to calculate the liquid pressure and force acting on one pistol in the below sections.

• Get the area and force of the first piston, area of the second piston.
• Divide the first piston force by the fist piston area.
• Multiply the result by the second piston area to get the force acting the second piston.
• The result from step 2 is the liquid pressure.

### What is Pascal's Law?

Pascal's law states that the external static pressure applied on a confined liquid is distributed or transmitted evenly throughout the liquid in all directions.

Pascal's principle is used in many hydraulic system. The system has two pistons one is having a smaller area and other is bigger area those are connected with each other using a hydraulic fulid.

Pascal's lae formula is

FΓéü/AΓéü = FΓéé/AΓéé

Where,

FΓéü is the force applied to the first piston

AΓéü is the area of the first piston

FΓéé is the force applied on the second piston

AΓéé is the area of the second piston

The pressure of the liquid of the hydraulic press can be calculated in two simple ways

p = FΓéü/AΓéü or p = FΓéé/AΓéé

Another simple formulas are along the lines

dΓéü = FΓéé/FΓéü * dΓéé

dΓéü = AΓéé/AΓéü * dΓéé

The work done by piston is W = FΓéü * dΓéü = FΓéé * dΓéé

Where

dΓéü is the distance at which the first piston has moved

dΓéé is the distance at which the second piston has moved

W is the total work done by the piston

Example

Question: Two pistons of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston?

Solution:

Given that

The radius of piston r = D/2

The diameter of smaller piston dΓéü = 5 cm

The diameter of the larger piston dΓéé = 60 cm

Area of smaller piston AΓéü = π(5/2)²

= 6.25π

Area of larger piston AΓéé = π(60/2)²

= 900π

Force of the larger piston FΓéé = (AΓéé/AΓéü)xFΓéü

= (900π)/(6.25π) x 50

= 7200 N

The force of the larger piston is 7200 N.

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### Frequently Asked Questions on Hydraulic Pressure Calculator

1. What determines the pressure in a hydraulic system?

The two factors that affect the hydraulic pressure are the surface area of the piston and the force acting the piston.

2. What are the applications of Pascal's law?

The applications of Pascal's law are hydraulic lift, pressure applied at piston A is transmitted equally to piston B without diminishing the use of the fluid that can't be compressed.

3. What is Pascal's Law Formula?

Pascal's law formula to find the force of the piston is FΓéü/AΓéü = FΓéé/AΓéé. The pressure acting the liquid is p = FΓéü/AΓéü or FΓéé/AΓéé.

4. What is the principle of Pascal’s Law?

Pascal's law says that pressure applied to an enclosed fluid will be transmitted without a change in magnitude to every point of the fluid and the walls of the container.