You can find the hydraulic pressure of a device easily by giving the required input details on Hydraulic Pressure Calculator. Enter the area, the force of the first piston and the area of the second piston of the hydraulic system and press the calculate button to obtain the liquid pressure and force of the second piston.

**Hydraulic Pressure Calculator: **Do you require any assistance in calculating the hydraulic pressure of the system? If yes, then read the following sections of this page. Here we have given useful details about Pascal's law, Pascal's principle and solved example questions. You can get also find the detailed manual steps to get the hydraulic pressure and force of a system using Pascal's law.

The hydraulic pressure acting on a system is calculated using Pascal's law. Obtain the simple steps to calculate the liquid pressure and force acting on one pistol in the below sections.

- Get the area and force of the first piston, area of the second piston.
- Divide the first piston force by the fist piston area.
- Multiply the result by the second piston area to get the force acting the second piston.
- The result from step 2 is the liquid pressure.

Pascal's law states that the external static pressure applied on a confined liquid is distributed or transmitted evenly throughout the liquid in all directions.

Pascal's principle is used in many hydraulic system. The system has two pistons one is having a smaller area and other is bigger area those are connected with each other using a hydraulic fulid.

Pascal's lae formula is

F₁/A₁ = F₂/A₂

Where,

F₁ is the force applied to the first piston

A₁ is the area of the first piston

F₂ is the force applied on the second piston

A₂ is the area of the second piston

The pressure of the liquid of the hydraulic press can be calculated in two simple ways

p = F₁/A₁ or p = F₂/A₂

Another simple formulas are along the lines

d₁ = F₂/F₁ * d₂

d₁ = A₂/A₁ * d₂

The work done by piston is W = F₁ * d₁ = F₂ * d₂

Where

d₁ is the distance at which the first piston has moved

d₂ is the distance at which the second piston has moved

W is the total work done by the piston

**Example**

**Question: Two pistons of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston?**

**Solution:**

Given that

The radius of piston r = D/2

The diameter of smaller piston d₁ = 5 cm

The diameter of the larger piston d₂ = 60 cm

Area of smaller piston A₁ = π(5/2)²

= 6.25π

Area of larger piston A₂ = π(60/2)²

= 900π

Force of the larger piston F₂ = (A₂/A₁)xF₁

= (900π)/(6.25π) x 50

= 7200 N

The force of the larger piston is 7200 N.

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** 1. What determines the pressure in a hydraulic system?**

The two factors that affect the hydraulic pressure are the surface area of the piston and the force acting the piston.

**2. What are the applications of Pascal's law?**

The applications of Pascal's law are hydraulic lift, pressure applied at piston A is transmitted equally to piston B without diminishing the use of the fluid that can't be compressed.

**3. What is Pascal's Law Formula?**

Pascal's law formula to find the force of the piston is F₁/A₁ = F₂/A₂. The pressure acting the liquid is p = F₁/A₁ or F₂/A₂.

**4. What is the principle of Pascal’s Law?**

Pascal's law says that pressure applied to an enclosed fluid will be transmitted without a change in magnitude to every point of the fluid and the walls of the container.