Created By : Sunil Kumar Gandipadala

Reviewed By : Phani Ponnapalli

Last Updated : Apr 10, 2023


Find the Velocity using Distance Method for d = 895 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.

 

Ex: 10,167,48 or 90

 

Distance
Time

Detailed Steps to find Velocity for d= 895 ft, t = 1 sec

We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.

So from the above sentence, we get the formula i.e

Velocity =
Distance / Time

Given that, Distance = 895 ft & Time = 1 sec

Substitute the given values in the formula

Velocity =
895 ft / 1 sec

∴ Velocity = 895.0 ft/sec



Velocity Results of d = 895 ft in t = 1 sec in different Units
Values Units
272.782688 m/s
982.017678 km/hr
894.956355 f/s
610.214874 mph
0.027278 km/s
0.5549 mi/s
53697.381286 ft/m
16366.961292 m/min
27278.26882 cm/sec