Find Velocity for d = 933 ft, t = 1 sec
Find the Velocity using Distance Method for d = 933 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 933 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 933 ft & Time = 1 sec
Substitute the given values in the formula
933 ft / 1 sec
∴ Velocity = 933.0 ft/sec
Velocity Results of d = 933 ft in t = 1 sec in different Units
| Values | Units |
|---|---|
| 284.364523 | m/s |
| 1023.712283 | km/hr |
| 932.954502 | f/s |
| 636.123438 | mph |
| 0.028436 | km/s |
| 0.57846 | mi/s |
| 55977.270101 | ft/m |
| 17061.871381 | m/min |
| 28436.452301 | cm/sec |
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