Gay-Lussac's Law Calculator is an user-friendly tool that needs initial parameters & final parameters to find the unknown value quickly. This calculator tool provides the output easily and gives the useful information about basic gas parameters during an isochoric transition.

**Gay-Lussac's Law Calculator: **Need help to learn Gay-Lussac's Law? Then you at the correct place. This page provides the details like what is the use of Gay-Lussac's Law, formula, and example questions. Also, find the step by step process on how to calculate the unknown parameters of gas using Gay-Lussac's Law.

Follow the simple guidelines mentioned below to get the unknown parameters of Gay-Lussac's Law in fraction of seconds.

- Get initial temperature, initial pressure and final temperature
- Multiply initial pressure, final temperature
- Divide the product by final temperature to get the final pressure value.

Gay Lussac’s law describes the relationship between the temperature and pressure of a gas when the amount of gas in a closed container is constant. It is also called as the pressure law.

Using the Gay Lussac’s law definition its formula can be written as

**P _{1}T_{2} = P_{2}T_{1}**

Where,

P_{1} is the initial pressure of gas

P_{2} is the final pressure of gas

T_{1} is the initial temperature of gas

T_{2} is the final temperature of the gas.

**Example**

**Question: The pressure of a gas in a cylinder when it is heated to a temperature of 450 K is 3.5 atm. What was the initial temperature of the gas if its initial pressure was 1.5 atm.**

**Solution:**

Given that

Initial pressure P_{1} = 1.5 atm

Final pressure P_{2} = 3.5 atm

Final temperature T_{2} = 450 K

As per Gay-Lussac’s Law, P_{1}T_{2} = P_{2}T_{1}

T_{1} = (P_{1}T_{2})/P_{2}

= (1.5 * 450)/3.5

= 675/3.5

= 192.85

Therefore, Initial temperature of gas in the cylinder = 192.85 K.

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** 1. What is Gay-Lussac’s Law?**

Gay-Lussac’s Law states that the pressure used by a gas proportional to the temperature of the gas when the mass is fixed and volume is constabt.

**2. What are the applications of Gay-Lussac’s Law?**

Gay-Lussac’s Law really works in our daily life. Those are tire pressure in various season, putting a hot pan into the cold water, lid on a saucepan.

**3. What is Gay-Lussac’s Law Equation?**

The Gay-Lussac’s Law equation at two different conitions is P₁/T₁ = P₂/T₂. Where, P₁, P₂ are initial and final pressure, T₁, T₂ are initial and final temperature.

**4. At a temperature of 250 K, the pressure of the gas in a deodrant is 2 atm. Find the pressure of the gas when it heated to 1000 K?**

Given that,

Initial pressure P_{1} = 2 atm

Initial temperature T_{1} = 250 K

Final temperature T_{2} = 1000 k

The Gay-Lussac’s Law formula to calculate the final pressure is P_{2} = (P_{1}T_{2})/T_{1}

= (2 * 1000)/250 = 2000/250 = 8