# Gay-Lussac's Law Calculator

Gay-Lussac's Law Calculator is an user-friendly tool that needs initial parameters & final parameters to find the unknown value quickly. This calculator tool provides the output easily and gives the useful information about basic gas parameters during an isochoric transition.

### How to Find Pressure or Temperature?

Follow the simple guidelines mentioned below to get the unknown parameters of Gay-Lussac's Law in fraction of seconds.

- Get initial temperature, initial pressure and final temperature
- Multiply initial pressure, final temperature
- Divide the product by final temperature to get the final pressure value.

### Gay-Lussac's Law Definition

Gay Lussac’s law describes the relationship between the temperature and pressure of a gas when the amount of gas in a closed container is constant. It is also called as the pressure law.

Using the Gay Lussac’s law definition its formula can be written as

**P1T2 = P2T1**

Where,

P1 is the initial pressure of gas

P2 is the final pressure of gas

T1 is the initial temperature of gas

T2 is the final temperature of the gas.

**Example**

**Question: The pressure of a gas in a cylinder when it is heated to a temperature of 450 K is 3.5 atm. What was the initial temperature of the gas if its initial pressure was 1.5 atm.**

**Solution:**

Given that

Initial pressure P1 = 1.5 atm

Final pressure P2 = 3.5 atm

Gay-Lussac's Law Calculator

Final temperature T2 = 450 K

As per Gay-Lussac’s Law, P1T2 = P2T1

T1 = (P1T2)/P2

= (1.5 * 450)/3.5

= 675/3.5

= 192.85

Therefore, Initial temperature of gas in the cylinder = 192.85 K.

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### Frequently Asked Questions on Gay-Lussac's Law Calculator

**1. What is Gay-Lussac’s Law?**

Gay-Lussac’s Law states that the pressure used by a gas proportional to the temperature of the gas when the mass is fixed and volume is constabt.

**2. What are the applications of Gay-Lussac’s Law?**

Gay-Lussac’s Law really works in our daily life. Those are tire pressure in various season, putting a hot pan into the cold water, lid on a saucepan.

**3. What is Gay-Lussac’s Law Equation?**

The Gay-Lussac’s Law equation at two different conitions is PΓéü/TΓéü = PΓéé/TΓéé. Where, PΓéü, PΓéé are initial and final pressure, TΓéü, TΓéé are initial and final temperature.

**4. At a temperature of 250 K, the pressure of the gas in a deodrant is 2 atm. Find the pressure of the gas when it heated to 1000 K?**

Given that,

Initial pressure P1 = 2 atm

Initial temperature T1 = 250 K

Final temperature T2 = 1000 k

The Gay-Lussac’s Law formula to calculate the final pressure is P2 = (P1T2)/T1

= (2 * 1000)/250 = 2000/250 = 8