Gay-Lussac's Law Calculator is an user-friendly tool that needs initial parameters & final parameters to find the unknown value quickly. This calculator tool provides the output easily and gives the useful information about basic gas parameters during an isochoric transition.
Gay-Lussac's Law Calculator: Need help to learn Gay-Lussac's Law? Then you at the correct place. This page provides the details like what is the use of Gay-Lussac's Law, formula, and example questions. Also, find the step by step process on how to calculate the unknown parameters of gas using Gay-Lussac's Law.
Follow the simple guidelines mentioned below to get the unknown parameters of Gay-Lussac's Law in fraction of seconds.
Gay Lussac’s law describes the relationship between the temperature and pressure of a gas when the amount of gas in a closed container is constant. It is also called as the pressure law.
Using the Gay Lussac’s law definition its formula can be written as
P1T2 = P2T1
P1 is the initial pressure of gas
P2 is the final pressure of gas
T1 is the initial temperature of gas
T2 is the final temperature of the gas.
Question: The pressure of a gas in a cylinder when it is heated to a temperature of 450 K is 3.5 atm. What was the initial temperature of the gas if its initial pressure was 1.5 atm.
Initial pressure P1 = 1.5 atm
Final pressure P2 = 3.5 atmGay-Lussac's Law Calculator
Final temperature T2 = 450 K
As per Gay-Lussac’s Law, P1T2 = P2T1
T1 = (P1T2)/P2
= (1.5 * 450)/3.5
Therefore, Initial temperature of gas in the cylinder = 192.85 K.
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1. What is Gay-Lussac’s Law?
Gay-Lussac’s Law states that the pressure used by a gas proportional to the temperature of the gas when the mass is fixed and volume is constabt.
2. What are the applications of Gay-Lussac’s Law?
Gay-Lussac’s Law really works in our daily life. Those are tire pressure in various season, putting a hot pan into the cold water, lid on a saucepan.
3. What is Gay-Lussac’s Law Equation?
The Gay-Lussac’s Law equation at two different conitions is P₁/T₁ = P₂/T₂. Where, P₁, P₂ are initial and final pressure, T₁, T₂ are initial and final temperature.
4. At a temperature of 250 K, the pressure of the gas in a deodrant is 2 atm. Find the pressure of the gas when it heated to 1000 K?
Initial pressure P1 = 2 atm
Initial temperature T1 = 250 K
Final temperature T2 = 1000 k
The Gay-Lussac’s Law formula to calculate the final pressure is P2 = (P1T2)/T1
= (2 * 1000)/250 = 2000/250 = 8