Hydraulic Pressure Calculator
You can find the hydraulic pressure of a device easily by giving the required input details on Hydraulic Pressure Calculator. Enter the area, the force of the first piston and the area of the second piston of the hydraulic system and press the calculate button to obtain the liquid pressure and force of the second piston.
Step by Step Process to Evaluate Acceleration
The hydraulic pressure acting on a system is calculated using Pascal's law. Obtain the simple steps to calculate the liquid pressure and force acting on one pistol in the below sections.
- Get the area and force of the first piston, area of the second piston.
- Divide the first piston force by the fist piston area.
- Multiply the result by the second piston area to get the force acting the second piston.
- The result from step 2 is the liquid pressure.
What is Pascal's Law?
Pascal's law states that the external static pressure applied on a confined liquid is distributed or transmitted evenly throughout the liquid in all directions.
Pascal's principle is used in many hydraulic system. The system has two pistons one is having a smaller area and other is bigger area those are connected with each other using a hydraulic fulid.
Pascal's lae formula is
FΓéü/AΓéü = FΓéé/AΓéé
Where,
FΓéü is the force applied to the first piston
AΓéü is the area of the first piston
FΓéé is the force applied on the second piston
AΓéé is the area of the second piston
The pressure of the liquid of the hydraulic press can be calculated in two simple ways
p = FΓéü/AΓéü or p = FΓéé/AΓéé
Another simple formulas are along the lines
dΓéü = FΓéé/FΓéü * dΓéé
dΓéü = AΓéé/AΓéü * dΓéé
The work done by piston is W = FΓéü * dΓéü = FΓéé * dΓéé
Where
dΓéü is the distance at which the first piston has moved
dΓéé is the distance at which the second piston has moved
W is the total work done by the piston
Example
Question: Two pistons of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston?
Solution:
Given that
The radius of piston r = D/2
The diameter of smaller piston dΓéü = 5 cm
The diameter of the larger piston dΓéé = 60 cm
Area of smaller piston AΓéü = π(5/2)²
= 6.25π
Area of larger piston AΓéé = π(60/2)²
= 900π
Force of the larger piston FΓéé = (AΓéé/AΓéü)xFΓéü
= (900π)/(6.25π) x 50
= 7200 N
The force of the larger piston is 7200 N.
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Frequently Asked Questions on Hydraulic Pressure Calculator
1. What determines the pressure in a hydraulic system?
The two factors that affect the hydraulic pressure are the surface area of the piston and the force acting the piston.
2. What are the applications of Pascal's law?
The applications of Pascal's law are hydraulic lift, pressure applied at piston A is transmitted equally to piston B without diminishing the use of the fluid that can't be compressed.
3. What is Pascal's Law Formula?
Pascal's law formula to find the force of the piston is FΓéü/AΓéü = FΓéé/AΓéé. The pressure acting the liquid is p = FΓéü/AΓéü or FΓéé/AΓéé.
4. What is the principle of Pascal’s Law?
Pascal's law says that pressure applied to an enclosed fluid will be transmitted without a change in magnitude to every point of the fluid and the walls of the container.