Evaluating Kinetic Energy for m 1070 lb and v = 1232 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 1070 lb, v = 1232 mph i.e. 73605267.5303 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 1070 lb, v = 1232 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 1070 lb & Velocity = 1232 mph:
Given that,
mass (m) = 1070 lb
velocity (v) = 1232 mph
⇒ Convert the mass 1070 lb to "Kilograms (kg)"
Mass in Kg = 1070 ÷ 2.204623
Mass in kg = 485.3438 kg
=> Convert Distance value 1232 mph to "meters (m)"
Distance in meters = 1232 x 1609
Distance in meters (m) = 550.7376 m
Substitute the value into the formula
KE = 73605267.5303 J
∴ Kinetic Energy (KE) = 73605267.5303 J
KE for m = 1070 lb, v = 1232 mph Results in different Units
Values | Units |
---|---|
73605267.53026 | joules (J) |
73605.26753 | kilojoules (kJ) |
73.605268 | megajoules (mJ) |
20445.924004 | watt hours (Wh) |
20.445924 | kilowatt hours (kWh) |
17592.07849 | kilocalories (kcal) |
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