Evaluating Kinetic Energy for m 3107 kg and v = 272 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 3107 kg, v = 272 mph i.e. 22967678.3498 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 3107 kg, v = 272 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 3107 kg & Velocity = 272 mph:
Given that,
mass (m) = 3107 kg
velocity (v) = 272 mph
=> Convert Distance value 272 mph to "meters (m)"
Distance in meters = 272 x 1609
Distance in meters (m) = 121.5914 m
Substitute the value into the formula
KE = 22967678.3498 J
∴ Kinetic Energy (KE) = 22967678.3498 J
KE for m = 3107 kg, v = 272 mph Results in different Units
| Values | Units |
|---|---|
| 22967678.349792 | joules (J) |
| 22967.67835 | kilojoules (kJ) |
| 22.967678 | megajoules (mJ) |
| 6379.915757 | watt hours (Wh) |
| 6.379916 | kilowatt hours (kWh) |
| 5489.406041 | kilocalories (kcal) |
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