Evaluating Kinetic Energy for m 3108 kg and v = 273 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 3108 kg, v = 273 mph i.e. 23144315.4698 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 3108 kg, v = 273 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 3108 kg & Velocity = 273 mph:
Given that,
mass (m) = 3108 kg
velocity (v) = 273 mph
=> Convert Distance value 273 mph to "meters (m)"
Distance in meters = 273 x 1609
Distance in meters (m) = 122.0384 m
Substitute the value into the formula
KE = 23144315.4698 J
∴ Kinetic Energy (KE) = 23144315.4698 J
KE for m = 3108 kg, v = 273 mph Results in different Units
Values | Units |
---|---|
23144315.469761 | joules (J) |
23144.31547 | kilojoules (kJ) |
23.144315 | megajoules (mJ) |
6428.981663 | watt hours (Wh) |
6.428982 | kilowatt hours (kWh) |
5531.62332 | kilocalories (kcal) |
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