Evaluating Kinetic Energy for m 3112 kg and v = 277 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 3112 kg, v = 277 mph i.e. 23858171.8563 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 3112 kg, v = 277 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 3112 kg & Velocity = 277 mph:
Given that,
mass (m) = 3112 kg
velocity (v) = 277 mph
=> Convert Distance value 277 mph to "meters (m)"
Distance in meters = 277 x 1609
Distance in meters (m) = 123.8266 m
Substitute the value into the formula
KE = 23858171.8563 J
∴ Kinetic Energy (KE) = 23858171.8563 J
KE for m = 3112 kg, v = 277 mph Results in different Units
| Values | Units |
|---|---|
| 23858171.856306 | joules (J) |
| 23858.171856 | kilojoules (kJ) |
| 23.858172 | megajoules (mJ) |
| 6627.275262 | watt hours (Wh) |
| 6.627275 | kilowatt hours (kWh) |
| 5702.239065 | kilocalories (kcal) |
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