Evaluating Kinetic Energy for m 3113 kg and v = 278 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 3113 kg, v = 278 mph i.e. 24038465.9271 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 3113 kg, v = 278 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 3113 kg & Velocity = 278 mph:
Given that,
mass (m) = 3113 kg
velocity (v) = 278 mph
=> Convert Distance value 278 mph to "meters (m)"
Distance in meters = 278 x 1609
Distance in meters (m) = 124.2736 m
Substitute the value into the formula
KE = 24038465.9271 J
∴ Kinetic Energy (KE) = 24038465.9271 J
KE for m = 3113 kg, v = 278 mph Results in different Units
| Values | Units |
|---|---|
| 24038465.92711 | joules (J) |
| 24038.465927 | kilojoules (kJ) |
| 24.038466 | megajoules (mJ) |
| 6677.356988 | watt hours (Wh) |
| 6.677357 | kilowatt hours (kWh) |
| 5745.330376 | kilocalories (kcal) |
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