Evaluating Kinetic Energy for m 3128 kg and v = 293 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 3128 kg, v = 293 mph i.e. 26831195.3493 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 3128 kg, v = 293 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 3128 kg & Velocity = 293 mph:
Given that,
mass (m) = 3128 kg
velocity (v) = 293 mph
=> Convert Distance value 293 mph to "meters (m)"
Distance in meters = 293 x 1609
Distance in meters (m) = 130.979 m
Substitute the value into the formula
KE = 26831195.3493 J
∴ Kinetic Energy (KE) = 26831195.3493 J
KE for m = 3128 kg, v = 293 mph Results in different Units
| Values | Units |
|---|---|
| 26831195.349318 | joules (J) |
| 26831.195349 | kilojoules (kJ) |
| 26.831195 | megajoules (mJ) |
| 7453.115782 | watt hours (Wh) |
| 7.453116 | kilowatt hours (kWh) |
| 6412.808626 | kilocalories (kcal) |
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