Evaluating Kinetic Energy for m 436 lb and v = 598 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 436 lb, v = 598 mph i.e. 7066307.9398 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 436 lb, v = 598 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 436 lb & Velocity = 598 mph:
Given that,
mass (m) = 436 lb
velocity (v) = 598 mph
⇒ Convert the mass 436 lb to "Kilograms (kg)"
Mass in Kg = 436 ÷ 2.204623
Mass in kg = 197.7662 kg
=> Convert Distance value 598 mph to "meters (m)"
Distance in meters = 598 x 1609
Distance in meters (m) = 267.3223 m
Substitute the value into the formula
KE = 7066307.9398 J
∴ Kinetic Energy (KE) = 7066307.9398 J
KE for m = 436 lb, v = 598 mph Results in different Units
| Values | Units |
|---|---|
| 7066307.939803 | joules (J) |
| 7066.30794 | kilojoules (kJ) |
| 7.066308 | megajoules (mJ) |
| 1962.864887 | watt hours (Wh) |
| 1.962865 | kilowatt hours (kWh) |
| 1688.887876 | kilocalories (kcal) |
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