Evaluating Kinetic Energy for m 528 lb and v = 690 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 528 lb, v = 690 mph i.e. 11392939.8953 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 528 lb, v = 690 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 528 lb & Velocity = 690 mph:
Given that,
mass (m) = 528 lb
velocity (v) = 690 mph
⇒ Convert the mass 528 lb to "Kilograms (kg)"
Mass in Kg = 528 ÷ 2.204623
Mass in kg = 239.4967 kg
=> Convert Distance value 690 mph to "meters (m)"
Distance in meters = 690 x 1609
Distance in meters (m) = 308.4488 m
Substitute the value into the formula
KE = 11392939.8953 J
∴ Kinetic Energy (KE) = 11392939.8953 J
KE for m = 528 lb, v = 690 mph Results in different Units
Values | Units |
---|---|
11392939.895344 | joules (J) |
11392.939895 | kilojoules (kJ) |
11.39294 | megajoules (mJ) |
3164.708058 | watt hours (Wh) |
3.164708 | kilowatt hours (kWh) |
2722.977575 | kilocalories (kcal) |
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