Evaluating Kinetic Energy for m 573 lb and v = 735 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 573 lb, v = 735 mph i.e. 14029203.0942 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 573 lb, v = 735 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 573 lb & Velocity = 735 mph:
Given that,
mass (m) = 573 lb
velocity (v) = 735 mph
⇒ Convert the mass 573 lb to "Kilograms (kg)"
Mass in Kg = 573 ÷ 2.204623
Mass in kg = 259.9084 kg
=> Convert Distance value 735 mph to "meters (m)"
Distance in meters = 735 x 1609
Distance in meters (m) = 328.565 m
Substitute the value into the formula
KE = 14029203.0942 J
∴ Kinetic Energy (KE) = 14029203.0942 J
KE for m = 573 lb, v = 735 mph Results in different Units
| Values | Units |
|---|---|
| 14029203.094244 | joules (J) |
| 14029.203094 | kilojoules (kJ) |
| 14.029203 | megajoules (mJ) |
| 3897.003977 | watt hours (Wh) |
| 3.897004 | kilowatt hours (kWh) |
| 3353.059506 | kilocalories (kcal) |
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