Evaluating Kinetic Energy for m 601 lb and v = 649 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 601 lb, v = 649 mph i.e. 11472750.9969 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 601 lb, v = 649 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 601 lb & Velocity = 649 mph:
Given that,
mass (m) = 601 lb
velocity (v) = 649 mph
⇒ Convert the mass 601 lb to "Kilograms (kg)"
Mass in Kg = 601 ÷ 2.204623
Mass in kg = 272.609 kg
=> Convert Distance value 649 mph to "meters (m)"
Distance in meters = 649 x 1609
Distance in meters (m) = 290.1207 m
Substitute the value into the formula
KE = 11472750.9969 J
∴ Kinetic Energy (KE) = 11472750.9969 J
KE for m = 601 lb, v = 649 mph Results in different Units
| Values | Units |
|---|---|
| 11472750.996863 | joules (J) |
| 11472.750997 | kilojoules (kJ) |
| 11.472751 | megajoules (mJ) |
| 3186.877826 | watt hours (Wh) |
| 3.186878 | kilowatt hours (kWh) |
| 2742.052883 | kilocalories (kcal) |
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