Evaluating Kinetic Energy for m 622 lb and v = 670 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 622 lb, v = 670 mph i.e. 12654462.1834 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 622 lb, v = 670 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 622 lb & Velocity = 670 mph:
Given that,
mass (m) = 622 lb
velocity (v) = 670 mph
⇒ Convert the mass 622 lb to "Kilograms (kg)"
Mass in Kg = 622 ÷ 2.204623
Mass in kg = 282.1344 kg
=> Convert Distance value 670 mph to "meters (m)"
Distance in meters = 670 x 1609
Distance in meters (m) = 299.5083 m
Substitute the value into the formula
KE = 12654462.1834 J
∴ Kinetic Energy (KE) = 12654462.1834 J
KE for m = 622 lb, v = 670 mph Results in different Units
| Values | Units |
|---|---|
| 12654462.183391 | joules (J) |
| 12654.462183 | kilojoules (kJ) |
| 12.654462 | megajoules (mJ) |
| 3515.131196 | watt hours (Wh) |
| 3.515131 | kilowatt hours (kWh) |
| 3024.488592 | kilocalories (kcal) |
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