Evaluating Kinetic Energy for m 630 lb and v = 792 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 630 lb, v = 792 mph i.e. 17909959.9565 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 630 lb, v = 792 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 630 lb & Velocity = 792 mph:
Given that,
mass (m) = 630 lb
velocity (v) = 792 mph
⇒ Convert the mass 630 lb to "Kilograms (kg)"
Mass in Kg = 630 ÷ 2.204623
Mass in kg = 285.7631 kg
=> Convert Distance value 792 mph to "meters (m)"
Distance in meters = 792 x 1609
Distance in meters (m) = 354.0456 m
Substitute the value into the formula
KE = 17909959.9565 J
∴ Kinetic Energy (KE) = 17909959.9565 J
KE for m = 630 lb, v = 792 mph Results in different Units
| Values | Units |
|---|---|
| 17909959.956462 | joules (J) |
| 17909.959956 | kilojoules (kJ) |
| 17.90996 | megajoules (mJ) |
| 4974.992857 | watt hours (Wh) |
| 4.974993 | kilowatt hours (kWh) |
| 4280.582516 | kilocalories (kcal) |
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