Evaluating Kinetic Energy for m 632 lb and v = 794 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 632 lb, v = 794 mph i.e. 18057673.0447 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 632 lb, v = 794 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 632 lb & Velocity = 794 mph:
Given that,
mass (m) = 632 lb
velocity (v) = 794 mph
⇒ Convert the mass 632 lb to "Kilograms (kg)"
Mass in Kg = 632 ÷ 2.204623
Mass in kg = 286.6703 kg
=> Convert Distance value 794 mph to "meters (m)"
Distance in meters = 794 x 1609
Distance in meters (m) = 354.9397 m
Substitute the value into the formula
KE = 18057673.0447 J
∴ Kinetic Energy (KE) = 18057673.0447 J
KE for m = 632 lb, v = 794 mph Results in different Units
| Values | Units |
|---|---|
| 18057673.044657 | joules (J) |
| 18057.673045 | kilojoules (kJ) |
| 18.057673 | megajoules (mJ) |
| 5016.024303 | watt hours (Wh) |
| 5.016024 | kilowatt hours (kWh) |
| 4315.886786 | kilocalories (kcal) |
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