Evaluating Kinetic Energy for m 673 lb and v = 835 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 673 lb, v = 835 mph i.e. 21266289.2909 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 673 lb, v = 835 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 673 lb & Velocity = 835 mph:
Given that,
mass (m) = 673 lb
velocity (v) = 835 mph
⇒ Convert the mass 673 lb to "Kilograms (kg)"
Mass in Kg = 673 ÷ 2.204623
Mass in kg = 305.2676 kg
=> Convert Distance value 835 mph to "meters (m)"
Distance in meters = 835 x 1609
Distance in meters (m) = 373.2678 m
Substitute the value into the formula
KE = 21266289.2909 J
∴ Kinetic Energy (KE) = 21266289.2909 J
KE for m = 673 lb, v = 835 mph Results in different Units
| Values | Units |
|---|---|
| 21266289.290875 | joules (J) |
| 21266.289291 | kilojoules (kJ) |
| 21.266289 | megajoules (mJ) |
| 5907.307307 | watt hours (Wh) |
| 5.907307 | kilowatt hours (kWh) |
| 5082.764358 | kilocalories (kcal) |
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