Evaluating Kinetic Energy for m 725 lb and v = 887 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 725 lb, v = 887 mph i.e. 25851690.5355 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 725 lb, v = 887 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 725 lb & Velocity = 887 mph:
Given that,
mass (m) = 725 lb
velocity (v) = 887 mph
⇒ Convert the mass 725 lb to "Kilograms (kg)"
Mass in Kg = 725 ÷ 2.204623
Mass in kg = 328.8544 kg
=> Convert Distance value 887 mph to "meters (m)"
Distance in meters = 887 x 1609
Distance in meters (m) = 396.5132 m
Substitute the value into the formula
KE = 25851690.5355 J
∴ Kinetic Energy (KE) = 25851690.5355 J
KE for m = 725 lb, v = 887 mph Results in different Units
| Values | Units |
|---|---|
| 25851690.535542 | joules (J) |
| 25851.690536 | kilojoules (kJ) |
| 25.851691 | megajoules (mJ) |
| 7181.030894 | watt hours (Wh) |
| 7.181031 | kilowatt hours (kWh) |
| 6178.701393 | kilocalories (kcal) |
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