Evaluating Kinetic Energy for m 740 lb and v = 902 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 740 lb, v = 902 mph i.e. 27286541.7258 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 740 lb, v = 902 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 740 lb & Velocity = 902 mph:
Given that,
mass (m) = 740 lb
velocity (v) = 902 mph
⇒ Convert the mass 740 lb to "Kilograms (kg)"
Mass in Kg = 740 ÷ 2.204623
Mass in kg = 335.6583 kg
=> Convert Distance value 902 mph to "meters (m)"
Distance in meters = 902 x 1609
Distance in meters (m) = 403.2186 m
Substitute the value into the formula
KE = 27286541.7258 J
∴ Kinetic Energy (KE) = 27286541.7258 J
KE for m = 740 lb, v = 902 mph Results in different Units
| Values | Units |
|---|---|
| 27286541.725751 | joules (J) |
| 27286.541726 | kilojoules (kJ) |
| 27.286542 | megajoules (mJ) |
| 7579.600987 | watt hours (Wh) |
| 7.579601 | kilowatt hours (kWh) |
| 6521.639006 | kilocalories (kcal) |
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