Evaluating Kinetic Energy for m 828 lb and v = 990 mph
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Kinetic Energy for m = 828 lb, v = 990 mph i.e. 36779382.0534 J using the Kinetic Energy Calculator in a fraction of seconds.
Ex: 10, 167, 48, 34.5 or 90
Detailed Solution finding Kinetic Energy for m = 828 lb, v = 990 mph
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared.
The formula to calculate Kinetic energy is:
Where,
KE = Kinetic Energy
m = Mass of object
v = velocity
Step by Step Solution to find Kinetic Energy of Mass = 828 lb & Velocity = 990 mph:
Given that,
mass (m) = 828 lb
velocity (v) = 990 mph
⇒ Convert the mass 828 lb to "Kilograms (kg)"
Mass in Kg = 828 ÷ 2.204623
Mass in kg = 375.5744 kg
=> Convert Distance value 990 mph to "meters (m)"
Distance in meters = 990 x 1609
Distance in meters (m) = 442.557 m
Substitute the value into the formula
KE = 36779382.0534 J
∴ Kinetic Energy (KE) = 36779382.0534 J
KE for m = 828 lb, v = 990 mph Results in different Units
| Values | Units |
|---|---|
| 36779382.053448 | joules (J) |
| 36779.382053 | kilojoules (kJ) |
| 36.779382 | megajoules (mJ) |
| 10216.503188 | watt hours (Wh) |
| 10.216503 | kilowatt hours (kWh) |
| 8790.481953 | kilocalories (kcal) |
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