Created By : awnish

Reviewed By : Phani Ponnapalli

Last Updated : Apr 10, 2023


Free Solenoid Inductance Calculator tool is helpful to calculate the self-inductance of a solenoid effortlessly & fastly. You have to enter the length, cross-section area, radius and number of turns details and hit the calculate button to check the inductance as output within no time.

Choose a Calculation
Number of turns(N):
Radius(r):
Length(l):

Step by Step Process to Calculate Inductance of Solenoid

Below provided are the steps for calculating the self-inductance of a solenoid easily.

  • Check the number of turns, radius, length of the solenoid.
  • Find the area of cross-section from the radius of the solenoid.
  • Multiply the square of number of tuns with the cross-section area and vaccum permeability.
  • Divide the product by the solenoid length to get the inductance of a solenoid.

Inductance of a Solenoid

A solenoid is a coil that is used in RLC Circuit. The characteristic inductance act as an interial element. The change in current flows through a coil is the self-induced potential difference.

The voltage in the solenoid is the ratio between the potential and the rate of change of current.

V = -L x dI/dt

The inductance of a solenoid can be stated as

L = µΓéÇ * N² * A/l

Where,

L is the self-inductance of a solenoid

N is the number of turns

r is the coil radius

A is the area of cross-section of the solenoid

l is the length

µΓéÇ is the vacuum permeability and its value is 1.25664 * 10-6 T*m/A

Example

Question: A solenoid has 33 turns and carries a current of 4 amps. It has a radius of 5 cm, length of 8 cm find its inductance?

Solution:

Given that

Number of turns of solenoid N = 33

Radius r = 5 cm

Length l = 8 cm = 0.08 m

Coss section area A = πr²

A = π x 5 x 5

= 78.54 cm² = 0.007854 m²

Inductance of the solenoid L = µΓéÇ * N² * A/l

L = 1.25664 x 10-6 x 33² * 0.007854/0.08

= 134.35 µH

Therefore, the inductance of a solenoid is 134.35 µH.

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FAQ's on Solenoid Inductance Calculator

1. What is the self-inductance of a solenoid?

A solenoid is a long, tightly wound coil. Self-inductance is a property of a current-carrying coil that resist the change of current flowing through it. In simple terms, the self-inductance of a solenoid is a phenomenon where the induction of a voltage in a current-carrying wire.


2. What is the inductance of a solenoid formula?

The inductance of a solenoid formula is L = µΓéÇ * N² * A/l. The parameters included are the number of turns, length of coil, area of the cross-section.


3. How does the solenoid inductance calculator works?

The inductance of a solenoid calculator gets the inductance of a coil easily by taking the required details such as the number of turns, radius, area of cross-section and length.


4. What are the uses of self-inductance?

The inductor stores the electrical energy in the form of a magnetic field. Self-inductance is used in filters, sensors, induction motors, chokes, turning circuits, transformers, ferrite beads and as relays.