Find Velocity for d = 803 ft, t = 1 sec
Find the Velocity using Distance Method for d = 803 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 803 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 803 ft & Time = 1 sec
Substitute the given values in the formula
803 ft / 1 sec
∴ Velocity = 803.0 ft/sec
Velocity Results of d = 803 ft in t = 1 sec in different Units
| Values | Units |
|---|---|
| 244.742457 | m/s |
| 881.072844 | km/hr |
| 802.960841 | f/s |
| 547.488875 | mph |
| 0.024474 | km/s |
| 0.49786 | mi/s |
| 48177.650472 | ft/m |
| 14684.547394 | m/min |
| 24474.245657 | cm/sec |
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