Find Velocity for d = 811 ft, t = 1 sec
Find the Velocity using Distance Method for d = 811 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 811 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 811 ft & Time = 1 sec
Substitute the given values in the formula
811 ft / 1 sec
∴ Velocity = 811.0 ft/sec
Velocity Results of d = 811 ft in t = 1 sec in different Units
| Values | Units |
|---|---|
| 247.180738 | m/s |
| 889.850655 | km/hr |
| 810.960451 | f/s |
| 552.94331 | mph |
| 0.024718 | km/s |
| 0.50282 | mi/s |
| 48657.627065 | ft/m |
| 14830.844255 | m/min |
| 24718.073758 | cm/sec |
Similar Velocity Calculation
Here are some examples Velocity by Distance Method