Find Velocity for d = 813 ft, t = 1 sec
Find the Velocity using Distance Method for d = 813 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 813 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 813 ft & Time = 1 sec
Substitute the given values in the formula
813 ft / 1 sec
∴ Velocity = 813.0 ft/sec
Velocity Results of d = 813 ft in t = 1 sec in different Units
| Values | Units |
|---|---|
| 247.790308 | m/s |
| 892.045108 | km/hr |
| 812.960354 | f/s |
| 554.306919 | mph |
| 0.024779 | km/s |
| 0.50406 | mi/s |
| 48777.621213 | ft/m |
| 14867.41847 | m/min |
| 24779.030783 | cm/sec |
Similar Velocity Calculation
Here are some examples Velocity by Distance Method