Created By : Sunil Kumar Gandipadala

Reviewed By : Phani Ponnapalli

Last Updated : Apr 10, 2023


Find the Velocity using Distance Method for d = 819 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.

 

Ex: 10,167,48 or 90

 

Distance
Time

Detailed Steps to find Velocity for d= 819 ft, t = 1 sec

We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.

So from the above sentence, we get the formula i.e

Velocity =
Distance / Time

Given that, Distance = 819 ft & Time = 1 sec

Substitute the given values in the formula

Velocity =
819 ft / 1 sec

∴ Velocity = 819.0 ft/sec



Velocity Results of d = 819 ft in t = 1 sec in different Units
Values Units
249.619019 m/s
898.628467 km/hr
818.960061 f/s
558.397745 mph
0.024962 km/s
0.50778 mi/s
49137.603657 ft/m
14977.141116 m/min
24961.901859 cm/sec