Created By : Sunil Kumar Gandipadala

Reviewed By : Phani Ponnapalli

Last Updated : Apr 10, 2023


Find the Velocity using Distance Method for d = 843 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.

 

Ex: 10,167,48 or 90

 

Distance
Time

Detailed Steps to find Velocity for d= 843 ft, t = 1 sec

We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.

So from the above sentence, we get the formula i.e

Velocity =
Distance / Time

Given that, Distance = 843 ft & Time = 1 sec

Substitute the given values in the formula

Velocity =
843 ft / 1 sec

∴ Velocity = 843.0 ft/sec



Velocity Results of d = 843 ft in t = 1 sec in different Units
Values Units
256.933862 m/s
924.961902 km/hr
842.958891 f/s
574.761048 mph
0.025693 km/s
0.52266 mi/s
50577.533435 ft/m
15416.031698 m/min
25693.386163 cm/sec