Find Velocity for d = 913 ft, t = 1 sec
Find the Velocity using Distance Method for d = 913 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 913 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 913 ft & Time = 1 sec
Substitute the given values in the formula
913 ft / 1 sec
∴ Velocity = 913.0 ft/sec
Velocity Results of d = 913 ft in t = 1 sec in different Units
| Values | Units |
|---|---|
| 278.26882 | m/s |
| 1001.767754 | km/hr |
| 912.955477 | f/s |
| 622.487351 | mph |
| 0.027827 | km/s |
| 0.56606 | mi/s |
| 54777.328619 | ft/m |
| 16696.129229 | m/min |
| 27826.882048 | cm/sec |
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