Find Velocity for d = 915 ft, t = 1 sec
Find the Velocity using Distance Method for d = 915 ft, t = 1 sec taking the help of Velocity Calculator by Distance Method in a matter of seconds.
Ex: 10,167,48 or 90
Detailed Steps to find Velocity for d= 915 ft, t = 1 sec
We know that the Velocity is defined as the rate change of displacement per unit time. Speed in a specific direction. Velocity is equal to distance divided by time.
So from the above sentence, we get the formula i.e
Distance / Time
Given that, Distance = 915 ft & Time = 1 sec
Substitute the given values in the formula
915 ft / 1 sec
∴ Velocity = 915.0 ft/sec
Velocity Results of d = 915 ft in t = 1 sec in different Units
Values | Units |
---|---|
278.878391 | m/s |
1003.962207 | km/hr |
914.955379 | f/s |
623.85096 | mph |
0.027888 | km/s |
0.5673 | mi/s |
54897.322767 | ft/m |
16732.703444 | m/min |
27887.839073 | cm/sec |
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