Find Acceleration due to Gravity for m = 1330 lb, r = 6 ft

Created By : Sunil Kumar Gandipadala

Reviewed By : Rajashekhar Valipishetty

Last Updated : Apr 10, 2023

Take the help of Acceleration due to Gravity Calculator to determine acceleration (a) for m = 1330 lb, r = 6 ft i.e. 1.2038 x 10-08 m/s2 in a short span of time.

 

Ex: 23, 456, 2e4 , 2e-11, 1.23, 3.076e-11

Mass of the object (M)
Radius of the object (R)

Find Acceleration due to Gravity for m = 1330 lb, r = 6 ft

Detailed Steps to Calculate Acceleration due to Gravity for m = 1330 lb, r = 6 ft

The Acceleration due to earth gravity is known as the acceleration due to gravity. It means when an object falls from a certain height towards the surface of the earth, its velocity changes.

The formula to calculate the acceleration due to gravity is given by:

a =
G x M / r2

Where,

a = Acceleration due to Gravity

G = Gravitational constant value (i.e. 6.674 x 10-11)

M = Mass of an object

r = Radius from planet centre


Step by Step Solution to find acceleration due to gravity of M = 1330.0 lb , and r = 6.0 ft :

Given that,

G = 6.674 x 10-11 N m2/kg2

M = 1330.0 lb

r = 6.0 ft

⇒ Convert the Mass value 1330.0 lb to "Kilograms (kg)"

Mass in Kg = 1330.0 ÷ 2.204623

Mass in kg = 603.27774862 kg

=> Convert radius value 6.0 ft to "meters (m)"

Radius in meters = 6.0 ÷ 3.281

Radius in meters (m) = 1.82879994 m

Substitute the value into the formula

a =
6.674 x 10-11 x 603.27774862 / (1.82879994)2

a = 1.2038 x 10-08 m/s2

∴ Acceleration due to Gravity (a) = 1.2038 x 10-08 m/s2

Acceleration due to Gravity for m = 1330 lb, r = 6 ft Results in different Units
Values Units
1.2038 x 10-08 meter per second squared (m/s2)
1.2038 x 10-06 centimeter per second squared (cm/s2)
3.9496 x 10-08 feet per second squared (ft/s2)
7.4804 x 10-12 mile per second squared (mi/s2)
1.2038 x 10-11 kilometer per second squared (km/s2)

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