Find Acceleration due to Gravity for m = 5364 g, r = 16 m

Created By : Sunil Kumar Gandipadala

Reviewed By : Rajashekhar Valipishetty

Last Updated : Apr 10, 2023

Take the help of Acceleration due to Gravity Calculator to determine acceleration (a) for m = 5364 g, r = 16 m i.e. 1.3984 x 10-12 m/s2 in a short span of time.

 

Ex: 23, 456, 2e4 , 2e-11, 1.23, 3.076e-11

Mass of the object (M)
Radius of the object (R)

Find Acceleration due to Gravity for m = 5364 g, r = 16 m

Detailed Steps to Calculate Acceleration due to Gravity for m = 5364 g, r = 16 m

The Acceleration due to earth gravity is known as the acceleration due to gravity. It means when an object falls from a certain height towards the surface of the earth, its velocity changes.

The formula to calculate the acceleration due to gravity is given by:

a =
G x M / r2

Where,

a = Acceleration due to Gravity

G = Gravitational constant value (i.e. 6.674 x 10-11)

M = Mass of an object

r = Radius from planet centre


Step by Step Solution to find acceleration due to gravity of M = 5364.0 g , and r = 16.0 m :

Given that,

G = 6.674 x 10-11 N m2/kg2

M = 5364.0 g

r = 16.0 m

⇒ Convert the Mass value 5364.0 g to "Kilograms (kg)"

Mass in Kg = 5364.0 ÷ 1000

Mass in kg = 5.364 kg

Substitute the value into the formula

a =
6.674 x 10-11 x 5.364 / (16.0)2

a = 1.3984 x 10-12 m/s2

∴ Acceleration due to Gravity (a) = 1.3984 x 10-12 m/s2

Acceleration due to Gravity for m = 5364 g, r = 16 m Results in different Units
Values Units
1.3984 x 10-12 meter per second squared (m/s2)
1.3984 x 10-10 centimeter per second squared (cm/s2)
4.588 x 10-12 feet per second squared (ft/s2)
8.6893 x 10-16 mile per second squared (mi/s2)
1.3984 x 10-15 kilometer per second squared (km/s2)

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