Find Acceleration due to Gravity for m = 660 g, r = 4 in
Created By : Sunil Kumar Gandipadala
Reviewed By : Rajashekhar Valipishetty
Last Updated : Apr 10, 2023
Take the help of Acceleration due to Gravity Calculator to determine acceleration (a) for m = 660 g, r = 4 in i.e. 4.2672 x 10-09 m/s2 in a short span of time.
Detailed Steps to Calculate Acceleration due to Gravity for m = 660 g, r = 4 in
The Acceleration due to earth gravity is known as the acceleration due to gravity. It means when an object falls from a certain height towards the surface of the earth, its velocity changes.
The formula to calculate the acceleration due to gravity is given by:
Where,
a = Acceleration due to Gravity
G = Gravitational constant value (i.e. 6.674 x 10-11)
M = Mass of an object
r = Radius from planet centre
Step by Step Solution to find acceleration due to gravity of M = 660.0 g , and r = 4.0 in :
Given that,
G = 6.674 x 10-11 N m2/kg2
M = 660.0 g
r = 4.0 in
⇒ Convert the Mass value 660.0 g to "Kilograms (kg)"
Mass in Kg = 660.0 ÷ 1000
Mass in kg = 0.66 kg
=> Convert radius value 4.0 in to "meters (m)"
Radius in meters = 4.0 ÷ 39.37
Radius in meters (m) = 0.10159995 m
Substitute the value into the formula
a = 4.2672 x 10-09 m/s2
∴ Acceleration due to Gravity (a) = 4.2672 x 10-09 m/s2
Acceleration due to Gravity for m = 660 g, r = 4 in Results in different Units
Values | Units |
---|---|
4.2672 x 10-09 | meter per second squared (m/s2) |
4.2672 x 10-07 | centimeter per second squared (cm/s2) |
1.4 x 10-08 | feet per second squared (ft/s2) |
2.6515 x 10-12 | mile per second squared (mi/s2) |
4.2672 x 10-12 | kilometer per second squared (km/s2) |
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