Find Specific Gravity if Density of Gasoline is 74 lb/cu ft

The formula for specific gravity, given that the reference substance is water, is the density of the object divided by the density of the water. Here, we use the Greek symbol Rho (ρ) to indicate density.

The Density of water is given by 997 kg/m³

Where,

Step by Step Solution to find Specific Gravity of 74 lb/cu ft :

Given that,

ρ object = 74 lb/cu ft

ρ H₂O = 997 kg/m³

⇒ Convert the Water Density unit kg/m³ to same as Material Density unit " lb/cu ft "

Water Density in lb/cu ft = 997 x 0.06243

Water Density in lb/cu ft = 62.24271 lb/cu ft

Substitute the value into the formula

Specific Gravity = 1.1889

∴ Specific Gravity = 1.1889

Here are some examples of Specific Gravity Calculation

• Specific gravity for material 75 lb/cu ft
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• Specific gravity for material 79 lb/cu ft