Determine Specific Gravity given Density of Gasoline is 76 lb/cu ft using the Specific Gravity Calculator in no time along with step by step procedure.
The formula for specific gravity, given that the reference substance is water, is the density of the object divided by the density of the water. Here, we use the Greek symbol Rho (ρ) to indicate density.
The Density of water is given by 997 kg/m3
Where,
ρ object = Density of an Object
ρ H2O = Density of Water
Step by Step Solution to find Specific Gravity of 76 lb/cu ft :
Given that,
ρ object = 76 lb/cu ft
ρ H2O = 997 kg/m³
⇒ Convert the Water Density unit kg/m³ to same as Material Density unit " lb/cu ft "
Water Density in lb/cu ft = 997 x 0.06243
Water Density in lb/cu ft = 62.24271 lb/cu ft
Substitute the value into the formula
Specific Gravity = 1.221
∴ Specific Gravity = 1.221
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