The charge that flows through the shower in 300 seconds is 18000C. The electric shower has a power of 13.8 kW. Calculate the resistance of the heating element in the shower.

GCSE

Firstly, we want to define what information we know from the question: ∆Q = 18000C; ∆t = 300s, P = 13.8kW
Therefore, to calculate the resistance we can use the power equation, P=I²R, and calculate the current from: change in charge/change in time.
Current, I = ∆Q /∆t Substituting into this equation the known values: I = 18000/300 = 60A
Now, using the power equation: P = 13800 = (60²)R Rearranging this to calculate resistance, R = 13800/3600 = 3.83 Ohms

Related GCSE Questions

The teacher quickly inverts the can containing boiling water into a bowl of cold water, as shown in the diagram. When the can is inverted in the cold water, the can collapses. Use ideas about particles and pressure to explain why the can collapses.
According to Newton's third law, every action has an equal and opposite reaction. Why then does a box move when I push it? Shouldn't the two opposing forces cancel out to a zero net force?
A mass of 2.5kg is raised by a height of 8m in 36 seconds using an electronic motor. Calculate the power of the motor.
What is the density of a rock (mass 75g) submerged in water which displaced by a volume of 37.5cm^3? SI units
How do stars form?

The charge that flows through the shower in 300 seconds is 18000C. The electric shower has a power of 13.8 kW. Calculate the resistance of the heating element in the shower.

Related GCSE Questions

Levels